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Algorithmically deleting children nodes of nodes that only have one child

I have a hierarchy with two levels (for simplicity). Level one (children) have two nodes, two (for simplicity). A Level two node has a child node, and so on.
Each node has a numerical value. The set of all values for a parent node form a line. The goal is to find a set of pointers to free up memory for that node’s children. Finding these pointers is easy, the problem is figuring out if we should delete or leave them.
Given the lines for each node, I need to determine the best decision:

delete children of a node that has only 1 child
delete children of a node that has two children and only the smaller one is unused.

The values are also percentages – the smaller is smaller and harder to reuse.
Update: With the current solution I can determine the best decision for level 0 and level 1. However, it does not scale to higher levels, nor does it scale to two levels. If a node has two children, level 2 has two more decisions to make.

Heuristics
This is a classic problem of optimization, and the obvious first step is to guess an approximate algorithm, after that you can work on validating or improving it.
My suggestion would be to guess that the main criterion to decide on what to do is to check if you can reuse any of the available children for some other purpose.
So the first thing to do, is to count how many children you have of each level, and what percentage is this level’s overall percentage of the total.
If there are many levels, and if the percentages are very uneven, then it suggests that the problem is “unbalanced”. In this case, you can use some heuristic to determine that and turn off those levels, rather than trying to manually reduce.
Otherwise, if you have a level that is small, with a lot of children, then it suggests that the problem is “balanced”. In this case, you can manually test to see if it is the case, to see if it can be set aside.
If it