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Furthermore, I have the following code:
import urllib.request, time, sys, os

if sys.stdout.isatty():
os.system(‘CLS’)

f = open(‘start.txt’, ‘r’)
start = f.readline()
f.close()

f = open(‘end.txt’, ‘r’)
f.seek(0)
end = f.readline()
f.close()

time.sleep(10)

def process_end(end):
f = open(‘start.txt’, ‘r’)
f.seek(0)
content = f.read()
f.close()
print(content)

if __name__ == “__main__”:
process_end(end)

and when I run the code as an external script, it worked correctly by reading the files ‘end.txt’ and’start.txt’.
The problem is when I run the code as a script, it doesn’t work and it won’t give any error. Below is the process that’s been happening:

I started running the code as an external script
The file’start.txt’ was opened by this code successfully
The content in’start.txt’ was printed on the terminal, as I expected
It then paused and waited for 10 seconds.
The file ‘end.txt’ wasn’t opened by this code

Could someone please explain to me why this happened?

when you run the code as a script, it works because the variables you get are not the ones you set. Instead the files are created in the current directory of the script and the files contained in start.txt and end.txt are created in the directories./start.txt and./end.txt
you can do one of the following to run the script as you expected:

remove os.system and use subprocess.call
remove time.sleep(10) and use the time.sleep(10) function in the script

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I am using this command:
sed -r’s/./& /’ $filename
The output of my command is the same except the first line has the I am using this command:
sed -r’s/./& /’ $filename
The output of my command is the same except the first line has the code Sincere thanks

Here are the modifications I made to your command to make it work:
sed -r -e’s/./,& /’

This removes the current line separator on your first line. In your case, you want to replace the comma with the newline, so you add a -r switch.
sed -r -e’s/./,
/’

Here we add a newline character between each character pair.
If you need it to work with a different character (like a tab), replace the newline with what you need.
sed -r -e’s/./,\t/’

However, I highly recommend that you use Awk instead. The sed -e… command is highly overrated.
Update:
It looks like you’re experiencing a similar problem as in this question. Here’s my answer to that question.
This might get you on your way:
sed -r ‘/[a-zA-Z0-9]{3}/{ s/
/,/g; s/,//; }’ input

This will print the original line if it contains 3 lower case letters, numbers, or spaces, but will replace those spaces with newlines.
You may also use tr instead of sed -e… to do the same thing (if you’re comfortable with the idea of changing the whole line if some condition is met).

#!/usr/bin/env bash

INPUT_FOLDER=$1
OUTPUT_FOLDER=$2

echo “This script is generated by k6dump_runner.sh, for more info refer to the script”

if [ -z $INPUT_FOLDER ];
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