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Pixel Game Maker MV MV [Ativador]

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Pixel Game Maker MV MV [Ativador]

 

You can also find this tutorial on our wiki
Pixel Game Maker MV MV [Ativador]

This tutorial is based on the free software provided by Pixel Game Maker MV. It does not cover the most recent version.
Pixel Game Maker MV MV [Ativador]

The latest Maker title provides a simple, fun way to make games with zero coding.

Use Pixel Game Maker MV to make your own 2D action games!

This tutorial will serve as the written version of Pixel Game Maker MV’s built-in side view tutorials.Q:

Find index of first duplicate of duplicate

Given a string a, can we find the index of first duplicate of duplicate that occur?
Consider the input “ababcd” can we find the index of first duplicate of duplicate that occur?

A:

Yes, you can.
The problem is equivalent to finding k duplicates in a sequence of length n if and only if k is a fixed point of the recursive function g(k)=g(k-1)+g(n-k), where g(k) is the number of duplicates with respect to the most recent duplication.
Hint 1: If there are p duplicates in a sequence of length n, the function g(k) is equal to k(n-k)/2.
Hint 2: The solution is also n/2 if k is the last duplication (as opposed to all the duplicates), but that doesn’t matter.
The solution is provided at Stackoverflow, here:

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Category:Video game scripting software
Category:Video game development softwareQ:

How to get value from a string of percentage value using regex in java?

Given below are strings of percentage values:

2.5%
10%
2.3%

and the requirement is to get the integer value from the same.
I have used StringTokenizer and substring to get the value. But couldn’t find a way to solve this issue.
A sample program is shown below:
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;

public class StringValue {
public static void main(String[] args) throws IOException {
String percentageValue = new File(“./input.txt”).getAbsolutePath();
int percentage = Integer.parseInt(percentageValue);
BufferedReader bufferedReader = new BufferedReader(new FileReader(percentageValue));

StringTokenizer tokenizer = new StringTokenizer(percentageValue, “,”);

while (tokenizer.hasMoreElements()) {
percentage = Integer.parseInt(tokenizer.nextToken());
}

System.out.println(percentage);
}
}

output:

0

A:

You can use the following regex and substring methods:
import java.util.regex.*;

public class RegexValue {
public static void main(String[] args) throws PatternSyntaxException, IOException {
String line = “2.3%”;
Matcher matcher = Pattern.compile(“\\d+%”).matcher(line);
if (matcher.find()) {
int percent = Integer.parseInt(matcher.group());
System.out.println(
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