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Q:
Get indices of elements in a list that satisfy a condition
Given an array of doubles, and a double, is there a built in method for getting the indices of elements of an array that satisfy a given condition?
e.g.,
Double[] elements = {23.5, 5.5, 4.8, 2.1, -1.2};
double tolerance = 1.0;
Integer[] indices = whatMethod(elements, tolerance);
System.out.println(indices);
The desired output would be {3, 1, 0} – since the element at index 3 satisfies the given condition.
A:
One way would be to use Arrays.binarySearch() in the Collections framework. The index of the element (the one with the key property closest to the one you’re looking for) is returned.
System.out.println(Arrays.binarySearch(elements, tolerance));
Alternatively, you could use a simple loop:
int index = -1;
for(int i = 0; i < elements.length; i++) {
if(elements[i] <= tolerance) {
index = i;
break;
}
}
(If you want the index for the element that satisfies the condition, you'd just omit the break.)
A:
You can achieve this in an array-based algorithm
Double[] elements = {23.5, 5.5, 4.8, 2.1, -1.2};
double tolerance =
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